WebApr 9, 2024 · If we write out the first few terms, you can see a pattern. 0, 1, 3, 7, 15, 31, 63 All of the numbers are of the form a n = 2 n − 1. The way we can see this from the recurrence is through induction: 2 ( 2 n − 1 − 1) + 1 = 2 n − 1 Now try evaluating a n = 3 a n − 1 + 2, and then a n = k a n − 1 + k − 1. Share Cite Follow edited Apr 9, 2024 at 0:34 WebIf A = 3 1 2 3 2 - 3 2 0 - 1 , find A^-1 Hence, solve the system of equation: 3x + 3y + 2z = 1 x + 2y = 4 2x - 3y - z = 5. Class 12. >> Maths. >> Determinants. >> Inverse of a Matrix …
Ex 3.3, 4 - Find (A + 2B)
WebMar 30, 2024 · Last updated at March 23, 2024 by Teachoo Question 24 (OR 1 st question) If A = [3 1 2 3 2 -3 2 0 -1], find A –1 Hence, solve the system of equations: 3x + 3y + 2z = 1 x + 2y = 4 2x – 3y – z = 5 Get live Maths 1-on-1 Classs - Class 6 to 12 Book 30 minute class for ₹ 499 ₹ 299 Transcript WebMar 30, 2024 · Ex 3.2, 15 Find A2 – 5A + 6I if A = [ 8(2&0&1@2&1&3@1&−1&0)] Finding A2 A2 = AA = [ 8(2&0&1@2&1&3@1&−1&0)] [ 8(2&0&1@2&1&3@1&−1&0)] = [ 8(2(2)+0(2)+1(1)&2(0 ... loot easy
If A = 2 - 3 5 3 2 - 4 1 1 - 2 , find A^-1 .Using A^-1 , solve the ...
WebMar 30, 2024 · If A = [3 1 2 3 2 -3 2 0 -1], find A^-1. Hence solve system equations. Class 12. Solutions of Sample Papers and Past Year Papers - for Class 12 Boards. CBSE … WebMay 3, 2014 · Let A be a 3 × 3 matrix with real entries such that det ( A) = 6 and t r ( A) = 0. If det ( A + I) = 0 ( I denotes 3 × 3 identity matrix), then the eigenvalues of A are: (iv) − 1, … WebIf a+b+c=0 and ∣a∣=3; ∣b∣=5; ∣c∣=7, find the angle between a vector and b A 60 0 B 30 0 C 45 0 D none of these Medium Solution Verified by Toppr Correct option is A) ∣a∣=3,∣b∣=4,∣c∣=5 a+b+c=0 a+b=−c ∣a+b∣=∣−c∣ ∣a+b∣ 2=∣−c∣ 2 ∣a∣ 2+∣b∣ 2+2a.b=∣c∣ 2 9+25+2a.b=49 Also ab=3×5 Hence 9+25+2abcosθ=49 15=30cosθ Or cosθ= 21 θ=60 0 … hori in maori